5a^2+7a+1=0

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Solution for 5a^2+7a+1=0 equation: 



5a^2+7a+1=0

a = 5; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·5·1
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{29}}{2*5}=\frac{-7-\sqrt{29}}{10}
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{29}}{2*5}=\frac{-7+\sqrt{29}}{10}
$

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